3Cos^2x+Sen^2x=2

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Solution for 3Cos^2x+Sen^2x=2 equation: 


Simplifying
3Cos2x + Sen2x = 2

Reorder the terms:
en2xS + 3os2xC = 2

Solving
en2xS + 3os2xC = 2

Solving for variable 'e'.

Move all terms containing e to the left, all other terms to the right.

Add '-3os2xC' to each side of the equation.
en2xS + 3os2xC + -3os2xC = 2 + -3os2xC

Combine like terms: 3os2xC + -3os2xC = 0
en2xS + 0 = 2 + -3os2xC
en2xS = 2 + -3os2xC

Divide each side by 'n2xS'.
e = 2n-2x-1S-1 + -3n-2os2CS-1

Simplifying
e = 2n-2x-1S-1 + -3n-2os2CS-1

Reorder the terms:
e = -3n-2os2CS-1 + 2n-2x-1S-1

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